Berikut ini source code untuk membuka file yang telah kita tentukan :
public class Modul2 {
/**
* @param args the command line arguments
*/
public static String readLine(InputStream is)throws IOException
{
String req = "";
int c;
while(true){
c = is.read();
req += (char)c;
if((char)c == '\n')
break;
}
return req;
}
public static void main(String[] args) {
try {
// TODO code application logic here
ServerSocket ss = new ServerSocket(6661);
while(true)
{
Socket s = ss.accept();
BufferedInputStream inp = new BufferedInputStream(s.getInputStream());
BufferedOutputStream out = new BufferedOutputStream(s.getOutputStream());
int c, line;
line = 0;
String req = "";
String path = "";
while(!(req = readLine(inp)).equals("\r\n")){
System.out.print(req);
if(line == 0){
int start = 5;
for(int i=start; true ; i++){
if(req.charAt(i) != ' '){
path += req.charAt(i);
}
else break;
}
}
line++;
}
System.out.print(req);
String body = "";
String response = ""; // Untuk balasan dari server agar diterima oleh browser
response = "HTTP/1.0 200 OK\r\n" +
"Content-Type: text/html\r\n" +
"Server: Bot\r\n" +
"\r\n";
FileInputStream ifs = new FileInputStream("C:\\Users\\Ryan\\Documents\\index.html"); // Direktori file yang dimasukkan
while((c = ifs.read()) != -1){ // Membaca baris text sampai nilai -1 atau NULL
response += (char) c;
}
out.write(response.getBytes());
out.flush();
inp.close();
inp.close();
s.close();
}
} catch (IOException ex) {
Logger.getLogger(Modul2.class.getName()).log(Level.SEVERE, null, ex);
}
}
}
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